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[glow=blue,1,900]I think we should just re-name this Um...Me123's questions thread ::)Ok I have dilema.My circuit consists of:2AA supply (3V)two 3.2+V 30mA white LEDs--wired in paralleltwo 1.7V 20mA red LEDs---wired in seriesWith being wired the way they are there is no need for a resistor right?.
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You may like to trace through the amplifier with the signal tracer project. Obviously, all the step cannot provide the good amplifier, since a transistor has a gain of at least 20 times, and sometimes an in-circuit gain of 100. Thus, this gain of amplifier about 20 x 20 x 20 or 8,000 times! But this is not so. My final project for my microelectronics class was to build a three-stage audio amplifier using only BJT transistors and basic components, i.e. resisters and capacitors. My design for this project was largely based off of a two-stage amplifier I had built for a previous lab exercise. I made initial calculations based on the design constraints provided, built a simulation. This power amplifier is designed for use in low voltage applications. This 2 channel amplifier is supplied by ±13.8 voltage sources. For audio amplification applications, each channel can output to one speaker. The voltage gain of this system is 12. All of the power transistors are.
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11 Differential Amplifier Circuits - 295 - and Vout2 = 2 V V out (d) out (c) − (11.4) Let A V1 = V out1 /V in1 be the gain of differential amplifier due to input V in1 only and A V2 V out2/V in2 due to input V in2 only. Then from superposition theorem, the output voltage V out is equal to V out = A V1 Vin1 + A V2 Vin2.After substituting V in1 and V in2 from equation (11.1) and (11.2), the.
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